(6x-7)^2+4=21

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Solution for (6x-7)^2+4=21 equation: 



(6x-7)^2+4=21

We move all terms to the left:

(6x-7)^2+4-(21)=0

We add all the numbers together, and all the variables

(6x-7)^2-17=0

We move all terms containing x to the left, all other terms to the right

(6x-7)^2=17

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